'>Write a program, using 25 or fewer lines of code, to count each occurrence of each lower-case letter in a string. Start your program by declaring a character array, msg, with a size of 30 of greater.

 char msg[MAX]; 

The user should then type a text string into the array:

 cin.getline(msg, MAX); 

Your program should now report the number of each character (a-z) found in the array: a face at the beach a – 4 b – 1 c – 2 d – 0 e – 3 f – 1 g – 0 h – 2 i – 0 j – 0 k – 0 l – 0 m – 0 n – 0 o – 0 p – 0 q – 0 r – 0 s – 0 t – 2 u – 0 v – 0 w – 0 x – 0 y – 0 z – 0 Here is one way of creating that output using characters in a loop:

 for (i=0; i<26; i++) cout << static_cast(i + 'a') << " - " << etc.. 

In order to count each occurrence of each lower-case letter in a string using 25 or fewer lines of code, we can use an array to keep track of the count for each letter.

First, we declare a character array called `msg` with a size of at least 30. The user is then prompted to type a text string into the array using `cin.getline(msg, MAX);`.

To count the occurrences of each letter, we will initialize an array called `count` with 26 elements, where each element represents a letter from ‘a’ to ‘z’. We will initialize all elements to 0. This can be done using `int count[26] = {0};`.

Next, we iterate over each character in the `msg` array. For each lowercase letter encountered, we increment the corresponding element in the `count` array. This can be achieved with a for loop that goes from 0 to the length of the string:

“`cpp
for (int i = 0; msg[i]; i++) {
if (msg[i] >= ‘a’ && msg[i] <= 'z') { count[msg[i] - 'a']++; } } ``` Inside the loop, we check if the character is a lowercase letter using `msg[i] >= ‘a’ && msg[i] <= 'z'`. If it is, we subtract 'a' from the character to get the index of the corresponding element in the `count` array. We then increment that element by 1. After counting the occurrences, we can print out the results. We iterate over the `count` array and print the number of occurrences for each letter. We can use another for loop for this: ```cpp for (int i = 0; i < 26; i++) { cout << static_cast(i + ‘a’) << " - " << count[i] << endl; } ``` Inside the loop, we use `static_cast(i + ‘a’)` to convert the index back to the corresponding lowercase letter. We then print the letter, followed by a hyphen and the count.

Putting it all together, the complete program would look like this:

“`cpp
#include
using namespace std;

int main() {
const int MAX = 30;
char msg[MAX];
int count[26] = {0};

cout << "Enter a text string: "; cin.getline(msg, MAX); for (int i = 0; msg[i]; i++) { if (msg[i] >= ‘a’ && msg[i] <= 'z') { count[msg[i] - 'a']++; } } cout << "Occurrences of each letter:" << endl; for (int i = 0; i < 26; i++) { cout << static_cast(i + ‘a’) << " - " << count[i] << endl; } return 0; } ``` This program will count the occurrences of each lowercase letter in the input string and display the results. It does so in fewer than 25 lines of code.