We are producing two types of products, product A and product B. Product A is defective if the weight is greater than 10 lbs. Product B is defective if the weight is greater than 15 lbs. For a given product, we know its product_type and its weight. Design a program to screen out defective products. Starting the program with variable definition: product_type = ‘xxx’ weight = xxx Hint: You need to figure out the product type first, and then check if the product is defective based on the weight. You may use a nested if statement like the following: if product is A: if product weight > 10: the product is defective else: if product weight >15: the product is defective But you need to translate the English into Python codes. As a challenge, you may also try a one-step if statement. such as : if is met: the product is defective else: the product is normal And the key is the bolded “

In order to design a program to screen out defective products, several variables need to be defined.

Firstly, we have two types of products: product A and product B. These types can be represented using a variable called “product_type”. For the purpose of this program, we will assign the value ‘A’ to product type A and ‘B’ to product type B.

Additionally, we need to define the weight of each product. This can be done using a variable called “weight”. The weight can be any numerical value.

To determine if a product is defective, we need to check its weight based on its product type.

To accomplish this, we can use an if statement. If the product type is ‘A’, we will check if the weight is greater than 10 lbs. If it is, we will consider the product defective. If the weight is not greater than 10 lbs, the product is considered normal.

Similarly, for product type ‘B’, we will check if the weight is greater than 15 lbs. If it is, the product is defective. If the weight is not greater than 15 lbs, the product is considered normal.

To translate this logic into Python code, we can use the if statement as follows:

“`python
if product_type == ‘A’:
if weight > 10:
print(“The product is defective”)
else:
print(“The product is normal”)

elif product_type == ‘B’:
if weight > 15:
print(“The product is defective”)
else:
print(“The product is normal”)
“`

Alternatively, we can simplify the code by using a nested if-else statement:

“`python
if product_type == ‘A’:
if weight > 10:
print(“The product is defective”)
else:
print(“The product is normal”)
else: # Assuming product_type == ‘B’
if weight > 15:
print(“The product is defective”)
else:
print(“The product is normal”)
“`

For the one-step if statement, we can use a logical operator to combine the conditions:

“`python
if product_type == ‘A’ and weight > 10 or product_type == ‘B’ and weight > 15:
print(“The product is defective”)
else:
print(“The product is normal”)
“`

In conclusion, by using the defined variables, product_type and weight, we can design a program that accurately screens out defective products. Through the use of if statements, the program will determine if a product is defective or normal based on its product type and weight.

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